(x-a)(x-b)(x-c)....(x-z)

Update : This puzzle is now solved

I consider this to be one of the more silly puzzle questions :p

Question

What is the value of this multiplication :

(x-a)(x-b)(x-c).....(x-z)

Answer

As rightly pointed out by Ajay and Kalpana, the answer is "zero".

The reason being, x-x = 0

Delete any node in the middle of a linked list

Question

Given a pointer to a node in the middle of a linked list, how will you delete the present node ?

Answer
  
  The trick is in using simple pointer tricks. The "present node" should now point to the "next node". Make sure you delete the data in the "present node"

void delete_node (list **node)
{

   list *present = *node;

   if (present == NULL)
        return;

[ use arrow in place of dot below ]

   *node = present.next; 
   free (present.data); 
   free (present);
   return;
}